Christopher | |
Technical Support | |
StableBit Scanner | |
2.5.2.3094 | |
Windows Server 2008 R2 | |
Alex | |
Alex | |
Ok, this is not simple. I'm going to post my analysis here because it's a lot of work and I want a record of it, just in case it comes up again.
typedef struct _DISK_GEOMETRY { LARGE_INTEGER Cylinders; MEDIA_TYPE MediaType; DWORD TracksPerCylinder; DWORD SectorsPerTrack; DWORD BytesPerSector; } DISK_GEOMETRY;
typedef struct _DISK_GEOMETRY_EX { DISK_GEOMETRY Geometry; LARGE_INTEGER DiskSize; BYTE Data[1]; } DISK_GEOMETRY_EX, *PDISK_GEOMETRY_EX;
E7 DA 01 00 00 00 00 00 0C 00 00 00 FF 00 00 00 3F 00 00 00 00 02 00 00 00 00 00 D4 E8 00 00 00 18 00 00 00 01 00 00 00 40 22 0E 53 6E 33 D6 45 AA 05 5C 69 83 BA 19 61 38 00 00 00 00 00 00 00 18 00 18 00 00 00 00 00 EA AC 85 DF 01 E0 FF FF 00 00 00 00 00 00 00 00 00 FC 92 DC 01 E0 FF FF 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
This decodes to:
0xe8d4000000 / (1024*1024*1024) = 931.3125So that's a drive size of 931.31 GB.
5A 04 FF 3F 37 C8 10 00 00 00 00 00 3F 00 00 00 00 00 00 00 20 20 20 20 20 20 38 4A 30 39 31 30 56 31 37 48 57 54 44 34 03 00 00 00 04 00 41 4A 41 30 35 42 30 36 50 41 4C 50 20 45 44 48 20 44 54 48 35 53 31 34 31 30 41 30 45 39 36 36 20 32 20 20 20 20 20 20 20 20 20 20 20 20 20 20 10 80 00 40 00 2F 00 40 00 02 00 02 07 00 FF 3F 10 00 3F 00 10 FC FB 00 10 01 FF FF FF 0F 00 00 07 00 03 00 78 00 78 00 78 00 78 00 00 00 00 00 00 00 00 00 00 00 00 00 1F 00 06 1F 04 00 5E 00 44 00 FC 01 28 00 6B 74 69 7D 23 61 69 74 49 BC 23 61 7F 40 6F 00 70 00 80 40 FE FF 00 00 00 00 00 00 00 00 00 00 00 00 00 00 B0 6D 70 74 00 00 00 00 00 00 00 00 03 60 6C 82 00 50 A6 CC D1 C6 7B A3 00 00 00 00 00 00 00 00 00 00 00 00 00 00 3C 40 3C 40 00 00 00 00 00 00 00 00 00 00 00 00 00 00 21 00 0B 00 00 00 00 00 82 21 F1 1C 00 FA 00 00 00 40 00 04 09 00 00 00 47 40 04 05 03 08 03 06 03 07 00 00 00 00 00 00 00 00 00 00 00 00 04 00 41 30 35 42 00 00 04 48 00 00 BD 5D 08 44 00 80 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 03 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 3D 00 00 00 00 00 00 40 00 00 00 00 00 00 00 00 00 00 00 00 00 00 18 15 00 00 DB 8D 00 00 00 00 1F 10 21 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 01 00 E0 03 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 A5 8C
This was a tough one and involved consulting the latest ACS spec.
Size of drive is:And that comes to 931.51 GB, which is slightly larger.
I'm guessing that because the Scanner starts to scan at the end of the drive, then those very last sectors can't be read (since they don't actually exist), and that's why you're seeing read errors.
I'm not sure how we can fix this, since the drive is telling us that it knows its size, and it's giving us that size.